??ANSWER TO EXERCISE 61

[ ParseNoun;
  if (WordLength(wn)==1 && WordAddress(wn)->0 == '#') return 1;
  return -1;
];
Back to the exercise in section 24
Mechanically translated to HTML from third edition as revised 16 May 1997. Copyright © Graham Nelson 1993, 1994, 1995, 1996, 1997: all rights reserved.